Question

In the given figure angle B= angle D = 90 degree and AB=DE. Prove that CD = .BCin the given figure angle

Answer 1

$\large{\orange{\underline{\red{\mathscr{GIVEN:-}}}}}$

AB=DE

B=D=90°

$\large{\orange{\underline{\red{\mathscr{PROVED \: \: THAT. }}}}}$

CD=BC.

$\large{\orange{\underline{\red{\mathscr{ANSWER:-}}}}}$

IN ΔABC & ΔEDC

AB=DE (GIVEN)

C=C (COMMOM ANGLE)

ABC=EDC(ANGLES ARE 90°)

.°.ΔABC=ΔEDC (BY USING S-A-A TEST)

. °. BC=DC (= Δ ‹-› SIDE)

HENCE PROVED.

$\large{\orange{\underline{\purple {\mathscr{THANKS.}}}}}$

Answer 2

CD = BC

Step-by-step explanation:

Given data:

ABC and CDE are two triangles.

To prove that CD = BD:

In ΔABC and ΔCDE,

∠B = ∠D = 90° (Angle)

AB = DE (side)

∠ACB = ∠DCE (Vertically opposite angles are equal)

Therefore, ΔABC ≅ ΔCDE by ASA congruence rule.

By corresponding parts of congruence triangles are equal.

⇒ CD = BC

Hence proved.

To learn more...

1. AD and BC are equal perpendiculars to a line segment AB . show that CD bisects AB.

https://brainly.in/question/667358

2. In the given figure. if AB=CD, AD = BC then prove. ΔADC ≅ ΔCBA

https://brainly.in/question/2476584