In the given figure angle c =90° and bc=12 cm then find tanA+tanB/cotA+cotB
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Step-by-step explanation:
tan A + tan B / cos A + cos B
tan a + tan b / 1/ tan a + 1/tan b
take LCM of the denominator
tan a + tan b / tan a + tan b / tan a * tan b
tan a+ tan b = tan a * tan b / tan a + tan b
after solving ,
tan a * tan b
tan 45° * tan 45° = 1 * 1 =1
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