In the given figure, angleB = angleE and angle1 = angle2. Show that angleABC =
angleAED.
D
The sides of triangular field
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Answer:
Given:
In quadrilateral ABCD, AB smallest & CD is longest sides.
To Prove:
∠A>∠C
& ∠B>∠D
Construction:
Join AC. Mark the angles as shown in the figure..
Proof:
In △ABC , AB is the shortest side.
BC > AB
∠2>∠4 …(i)
[Angle opposite to longer side is greater]
In △ADC , CD is the longest side
CD > AD
∠1>∠3 …(ii)
[Angle opposite to longer side is greater]
Adding (i) and (ii), we have
∠2+∠1>∠4+∠3
⇒∠A>∠C
Similarly, by joining BD, we can prove that
∠B>∠D
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