Question

in the given figure , AOB is a diameter of a circle and AOC=104° find angle BDC​

Answer 1

Step-by-step explanation:

angle COB = 180 - 104 = 76

angle BDC = 1÷2 ×76 by inscribed angle theorem

therefore angle BDC = 38

Answer 2

Answer:

join AD

then ADB is 90...angle in a semicircle..

ADC = 1/2* 104

ADC+CDB= 90

BDC= 38

YAYA