Question

in the given figure AOB is a line. Find the measure of angleAOD, angleDOC and angleBOC.
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Answer 1

Answer:

given

angleAOD is equal to x+10 and BOC is equal to x+20 and DOC is x

then angle AOD +angleDoc+angleBOC is equal to 180 degrees since linear triple

then

x+10 +x+x+20is equal to 180

3x+30 is equal to 180

3x ie equal to 180 -30

then 3x is equal to 150

x is equal to 150 /3

x equal to 50

then angle AOD is equal to 60 angleDOC is equal to 50 angle BOCequal to 70

Answer 2

From the given fig,

.we can observe that,

angle AOD + angleDOC + angleBOC

,=180 degree ( linear angle)

=} X + (X+10) + (X+20) =180

=}X + X +10 +X + 20 =180

=} 3x + 30 =180

=} 3x =180–30

=} X = 150/3

=50

angle AOD(x)=50

angle DOC ( x + 10) =60

&angle BOC (x + 20) =70

(we have asked the value of x=50 with

(x +10) & ( x +20 ).