Question

In the given figure AOB is a straight line angle AOC=(3×-8)° angle COD=50° and angle BOD=(x+10). The value of x is?

Answer 1

(3x-8)°+50°+(x+10)° = 180°
( By angle sum property )
3x+x-8+10+50°=180°
4x+2+50°=180°
4x+52°=180°
4x=180°-52°
4x=128°
x=128\4
x=32°

Answer 2

Step-by-step explanation:

3x+x-8+10+50=180

4x+52=180

4x=180-52

4x=128

x=128 / 4

x= 32