Question

In the given figure , ∠AOB= X+20° , ∠DOC= X+10° , ∠BOC= X ,find the value of ‘x’.
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Answer 1

1. Answer:

x+20°+x+10°+x=180°

30°+3x=180°

3x=180°-30°

3x=150°

x=150÷3

x=50°

I hope my answer right