In the given figure, Ap and AQ
two tangents
to the circle
with its contre at
at O so that PAQ = 90°
if AP and AQ is 3cm find the diameter of the circle
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Answer:
Given :
AP and AQ are tangents to the circle .
<POQ = 110° ,
<OPA = <OPA = 90°
( Since , Radius is perpendicular to the
tangent at point of contact )
In Quadrilateral POQA ,
<POQ + <OPA + <OQA + <PAQ = 360°
110° + 90° + 90° + <PAQ = 360°
290° + <PAQ = 360°
<PAQ = 360° - 290°
<PAQ = 70°
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