Question

In the given figure,BADll EF ,angleAEF=55° and angleACB=25°,find angleABC.

Answer 1

Angle fea = angle eab
therfore eab = 55
therfore cab = 180 -55 
=125
therfore 
abc = 180 - 25 - 125 ( angle sum property )
abc = 30 degree

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Answer 2

AD is parallel to EF so by Co interior angles on the same side of transversal AE so angle DAE will be 125degrees then BAC also will be 125degrees then in triangle ABC, by angle sum property of a triangle, angle ABC will be 30degrees