Question

in the given figure BC=CE and/_1=/_2. Prove that ∆GCB≈∆DCE
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Answer 1

Answer:

In triangle GCB and DCE-

• ∠GCB=∠DCB          (Oppsoite angles). A
• BC=DE.                    (given).                 S
• ∠GBC=∠DEC.         (Given that 1=2).     A

Hence ΔGCB≅ΔDCE by ASA congruecy criterion

I hope it helps...

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Answer 2

Step-by-step explanation:

it will hwlp you for that :)