Question

In the given figure, BC is a diameter of a circle with centre O. If angle BAO=65^ find angle AOC and angle ADC​

Answer 1

Answer:

Step-by-step explanation:

The lines BO and AO are equal in length (both radii of the circle).

So triangle BAO is isosceles

Therefore < ABO = < BAO = 65 degrees.

< AOC  = < ABO + <BAO = 65+65 = 130 degrees. (External Angle of a Triangle theorem).

< ADC = 1/2 * < AOC = 65 degrees (angle subtended at the centre = 2 * angle subtended at the circumference, by the same arc).