Math, asked by deven3994, 1 day ago

Short questions- a) Add ( 3X + 11 + 9Z ) and ( 6X – 5 – Z ) b) Subtract (6a2 – 7ab + 4b2) from (3ab – 5a2 +3b2) c) What should be the value of a if the value of 2x2 + x – a equals to 5, when x = 0? d) Find the value of 20 + 30 + 40. e) Write 2569874 in expanded form.​

Answers

Answered by ipshitach2207
0

Answer:

a)9x+6+8z

b)11a2-10ab+1b2

c)a=1

d)90

e)2000000+500000+60000+9000+800+70+4

Step-by-step explanation:

a) 3x+11+9z

+6x- 5 -1z

=9x+ 6+8z (copy the signs and add the numbers)

b) 6a2-7ab+4b2

-5a2+3ab+3b2

+ - - (change the signs)

=+11a2-10ab+1b2

c)2×2+x-a=5

x=0(given)

4+0-a=5

a=5-4

a=1

d)20+30+40=90

Similar questions