In the given figure BC is a diameter of the circle and angle BAO =60 ° . Then angle ADC is equals to ?
please mention the steps also
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Answer:
In ΔAOB,
∠OBA = ∠BAO
[angles opposite to equal sides are equal]
∠OBA = 60° [∴ ∠BAO = 60°, given]
∠ABC=∠ADC
[angles in the same segment AC are equal]
∠ADC = 60°
hope it helps
tq./
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60° is the correct answer
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