Question

In the given figure BC is produced to D and angle BAC = 40deg and angle ABC = 70deg. Find the value of ACD:

Answer 1

Answer:

110°

Step-by-step explanation:

given, angle ABC=70°

angleBAC=40°

by angle sum property

in a ∆ABC

A+B+C=180°

40°+70°+ACB=180°

angle ACB=180°-110

angle ACB=70°

BY LINEAR PAIR

angle ACB+angle ACD=180°

70°+ angleACD=180°

angle ACD180°=70°

angle ACD=110°

Answer 2

As we all know that the sum of all angles in a triangle is equal to 180°.

so,

angle BAC + Angle ABC + Angle ACB = 180°

40° + 70° + ACB = 180°

110° + ACB = 180°

Angle ACB = 180° - 110°

Angle ACB = 70°

Now we need to find Angle ACD.

As we know that the angle of a straight line is equal to 180°.

so,

Angle ACB + Angle ACD = 180°

70° + ACD = 180°

ACD = 180° - 70°

ACD = 110°