In the given figure bc of triangle is produced both the directio .prove that sum of the two interior angle so formed greater than 180.
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Step-by-step explanation:
If we extend BC on both ends, then the angles would be,
∠ACD=180−C
∠ABF=180−B
Sum of the 2 exterior angles=∠ACD+∠ABF
=(180−C)+(180−B)
=360−(B+C)
=360−(180−A)=180+A
∠A is always positive.
∴ sum of the angles is greater than 180°.
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