In the given figure, BD 1 AC and CE I AB. If BD=CE=3.5 cm and AB = 5 cm, then the measure of AC is (a) 3.5 cm ) (b) 4.5 cm (c) 5 cm .
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Solution :-
given that,
→ BD ⟂ AC .
→ CE ⟂ AB .
→ BD = CE = 3.5 cm
→ AB = 5 cm .
So, in ∆ADB and ∆AEC we have,
→ ∠ADB = ∠AEC { Each 90° }
→ ∠DAB = ∠EAC { common }
→ BD = CE { given }
then,
→ ∆ADB ~ ∆AEC { By AAS congruence rule }
therefore,
→ AB = AC { By CPCT }
hence,
→ AC = 5 cm (c) (Ans.)
Learn more :-
In the figure ∠ MNP = 90°, ∠ MQN = 90°, , MQ = 12 , QP = 3 then find NQ .
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