Question

In the given figure BD and CE are altitudes of Δ ABC and BD = CE.

(i) Is ΔBCD ≅ ΔCBE?

(ii) State the three pairs or matching parts you have used to answer (i)

Answer 1

Answer:

By RHS congruence condition if hypotenuse and one side of one right triangle are equal to hypotenuse and one side of other right triangle then both right triangles are congruent.

It is given that BD=CE and BC is the hypotenuse of small triangles CEB and BDC

So, In right triangles BCD and CBE

BC=CB=common side⋯⋯[hypotenuse]

And BD=CE=given⋯⋯[sides of right triangles]

So, by RHS condition

△BCD≅△CBE

Step-by-step explanation:

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