in the given figure below a square has been divided into two rectangle.if sum of the perimeters of the two rectangles is 54cm,what is the perimeter of the squre in cm
Answers
Answer:
36
Step-by-step explanation:
2(l+b)=54
l+b=27
2b+b=27
b=9,
b=a=9
Perimeter of square-9×4=36 cm
Given : square has been divided into two rectangle
the sum of the perimeter of the rectangle is 54 CM
To Find : perimeter of the square
Solution:
Let say square side = a cm
perimeter of square = 4a cm
Square is divide into 2 rectangles
Hence one line parallel to one side of square will divide adjacent side in two sides
Let say two sides are b and c where b + c = a
so we get two rectangles
one is with sides a , b and another with sides a , c
Sum of Perimeter of rectangles = 2 (a + b) + 2(a + c)
= 2(2a + b + c )
= 2 (2a + a)
= 2 (3a)
= 6a
6a = 54
=> a= 9
=> 4a = 36 cm
perimeter of the square is 36 cm
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