Question

In the given figure below AN = AC ,∆ BAC = 52° and ∆ACK = 84°, BCK is a st.Line. prove that NB=NC​

Answer 1

In ΔBACand Δ ACK

AN = NC (given)

angle ABC+BAC=angleACK (sum of angle=opposite exterior angle)

NC=NC(common side)

Hence, ΔBAC=ΔACK (By SAS condition)

so, NB=NC (CPCT)

therefore,

It is proved that NB=NC