Question

In the given figure bm and dn are both perpendicular to the line segment ac and bm is equal to dn prove that ac bisect bd.

Answer 1

Hi,

Where is the figure......

Answer 2

Answer:

$\huge \fbox \orange{✯AɴSᴡᴇR✯}$

In triangle BMO and triangle DNO

ANGLE BOM = vertically opposite angle DON

Angle OMB = Angle OND = 90 degree.

BM = DN [Given]

The triangles are congruent by AAS.

OB = OD

MN bisect BD

Therefore, AC bisects BD.