Question

perimeter of a right angle triangle is 60 and hypotenuse is 26 cm find the other two sides

Answer 1

$x + y + z = 60 \\ z = 26 \\ x + y = 34 \\ {z}^{2} = {x}^{2} + {y}^{2} \\ 676 = {x}^{2} + {y}^{2} \\ \\ {(x + y)}^{2} = {34}^{2} \\ 2xy = {34}^{2} - {26}^{2} \\ 2xy = 480 \\ xy = 240$
Now x and y are the roots of
${t}^{2} - 34t + 240 = 0$
On solving, we get
$x = 10 \\ y = 24$

Answer 2

$\huge\bf{Answer:-}$

x+y+z=60

z=26 x+y=34

z 2 =x² +y²

676=x² +y²

(x+y)² =34²

2xy=34² −26²

2xy=48

Now x and y r root

$\bf{t}^{2} - 34t + 240 = 0t$

$\bf\begin{lgathered}x = 10 \\ y = 24\end{lgathered}$