In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC =?
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Answer:
⇒ In △ABC,
⇒ ∠BCA=90
o
[ Angle inscribed in semi-circle ]
⇒ AC=BC [ Given ]
∴ ∠ABC=∠CAB [ Opposite angles of equal sides are equal ]
∴ ∠CAB+∠ABC+∠BCA=180
o
∴ ∠CAB+∠CAB=90
o
=180
o
∴ 2∠CAB=180
o
−90
o
∴ 2∠CAB=90
o
∴ ∠CAB=45
o
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