Question

In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC =?

Answer 1

Answer:

⇒ In △ABC,

⇒ ∠BCA=90

o

[ Angle inscribed in semi-circle ]

⇒ AC=BC [ Given ]

∴ ∠ABC=∠CAB [ Opposite angles of equal sides are equal ]

∴ ∠CAB+∠ABC+∠BCA=180

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∴ ∠CAB+∠CAB=90

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=180

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∴ 2∠CAB=180

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−90

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∴ 2∠CAB=90

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∴ ∠CAB=45

o