In the given figure ,calculate the force on the charge q if 'o' is the mid point of line ab.
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Answer:
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Explanation:
Since charge Q is placed at mid-point. So, force due to +q at A on Q is equal and opposite to force due to charge +q at B. So, net force on Q = 0.
i.e, Force on Q due to +q at A is
4πε
o
1
(r/2)
2
along AO.
Force on Q due to +q at B =
4πε
o
1
(r/2)
2
along BO.
The net resultant force is zero.
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