Question

In the given figure CB || QR and CA || PR. If AQ = 12 cm, AR = 20 cm and PB = CQ = 15 cm,
find PC and BR.​

Answer 1

HEY MATE YOUR ANSWER IS HERE

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IN TRIANGLE PQR

AC||PR (GIVEN)

HENCE

$\frac{qc}{cp} = \frac{qa}{ar}$

(by BPT THEOREAM)

hence

$\frac{15}{cp } = \frac{12}{20}$

NOW ...

CP =

$\frac{15}{12} \times 20$

hence

CP = 25cm -----------eq 1

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NOW IN TRIANGLE PQR AGAIN.....

CB || QR ( GIVEN )

HENCE

$\frac{pc}{qc} = \frac{pb}{br}$

( BY BPT THEOREAM )

HENCE

from eq 1 value of PC = 25 cm

$\frac{25}{15} = \frac{15}{br}$

HENCE BR =

$\frac{15}{25} \times 15$

hence

BR = 9 cm

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THANKS FOR THE QUESTION

HOPE IT HELPS ☺️☺️☺️☺️☺️☺️☺️

Answer 2

Answer:

here AC || PR

SO,

AQ/AR = QC/CP

12/20 = 15/CP

CP = (15 × 20)/12

CP = 25cm..

similarly

CB || QR

SO,

PC/CQ = PB/BR

25/15 = 15/BR

BR = (15 × 15)/25

BR = 9cm....

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