in the given figure CD parallel to EF find the value of x plzzz help me
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since CD parallel to EF and AC is an extension of CD
therefore AC||CD
Now,EC is a transversal between AC||CD
SO...FEC=ACE[Alternate angles]
NOW...
ACB=180-ACE[Linear pair]
Now according to angle sum property of triangles,
ACB+CAB+ABC=180
120+x+25=180
x+145=180
x=180-145
x=35°
There you go!
Have a nice day
therefore AC||CD
Now,EC is a transversal between AC||CD
SO...FEC=ACE[Alternate angles]
NOW...
ACB=180-ACE[Linear pair]
Now according to angle sum property of triangles,
ACB+CAB+ABC=180
120+x+25=180
x+145=180
x=180-145
x=35°
There you go!
Have a nice day
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I guess I am looking for this sum too...
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