Question

In the given figure CE is a tangent to the circle at point C.ABCD is a cyclic quadrilateral.If the angle ABC=93° and angle DCE=35°.Find angle ADC, angle CAD and angle ACD

Answer 1

See the attachment .I have used the property of cyclic quadrilateral in which the sum of opposite angles is 180 degree .

Answer 2

Angle ACD = 58°,CAD = 35°,ADC = 87°.

•By applying property of cyclic quadrilateral.

• the sum of opposite angles is 180°.

•angle ADC = 180°- Angle ABC

= 180 - 93°

•angle CAD = angle of CAD = DCE.

•In triangle ACD,

Angle of (ACD+CDA+DAC ) = 180°

Angle of ACD +87°+35° = 180°.

Angle of ACD = 180°-122° = 58°.