Question

In the given figure, chord AB
subtends an angle of 115° at the
centre O of a circle of 20 cm radius.
Calculate AB correct to the nearest cm.​

Answer 1

Answer:

Step-by-step explanation:

In OAM

OA=OB=20

∠A = ∠B

(Isosceles angle Therom)

∠ A= ∠ B=x

x +x+∠ O =180

x+x+115=180

x = 37.5

Draw OM Perpendicular toAB

A-M-B

In AOM

∠AOM+ ∠M +∠A=180

y+90+37.5=180

y=∠AOM=52.5

In AOM

Sin 52.5= AM/OA

0.787=AM/20

AM=15.74

Similarly

In BOM

BM=15.74

AB=AM+BM

AB=15.74+15.74

AB=31.48

Answer 2

Answer:

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