Question

In the given figure chords AB and CD of a circle intersect at O.AO=5 cm,BO=3 cm and CO=2.5 cm.Then the length of DO​

Answer 1

The length of  DO=6 cm

Step-by-step explanation:

AB and CD are chords  of circle and  intersect at O.

OA=5 cm

BO=3 cm

CO=2.5 cm

By using intersecting chord theorem

$AO\times BO=CO\times DO$

Substitute the values

$5\times 3=2.5\times DO$

$DO=\frac{5\times 3}{2.5}=6 cm$

Hence, DO=6 cm

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