In the given figure, circles with centres C and
D intersect at points P and Q. If AB is parallel
to CD and AB = 10 cm, then find the length of
CD
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5
Answer:
5
Step-by-step explanation:
we one that if you draw a perpendicular line from the centre to chord then that line will bisect that line so AM= MP and NP=NB
and we know that AB= AM+MP+NP+NB
AB= 2(MP+PN)---eq1
because AM=MP and NP=NB
and from the figure if you see
CDNM is a rectangle
so NM=CD
from eq1
NM= 10/2=5
so CD=5
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