Question

In the given figure, D and E are the points on the
base BC of AABC such that BD = СЕ, ,
AD = AE. Prove that AABE = AACD.​

Answer 1

Step-by-step explanation:

given D and E are the points on BC,

BD = CE and AD = AE

in triangle ADE, AD = AE

so the opposite angles of the equal sides are equal so angle ADE = angle AED

in triangles

• ABE and ACD

AE = AD

angle AEB = angle ADC

BE = CD

hence triangle ABE = triangle ADC