in the given figure, D is any point on the side BC of triangle ABC. show that AB + BC + CA > 2AD.
Answers
Answered by
18
Step-by-step explanation:
in triangle ABD
AB+BD>AD........ (1)
In triangle ADC
DC+CA>AD......... (2)
on adding (1) and (2)
AB+BD+DC+CA>2AD
on putting BD+DC=BC
AB+BD+CA>2AD
hence proved
hope it helped you
thank you
Answered by
22
Answer:
In ABD , By Inequality property of triangle
AB + BD > AD ----------(1)
And In ACD ,By Inequality property of triangle
DC + AC > AD ---------(2)
On Adding Eq (1) and Eq (2)
AB+BD+DC+AC> AD+AD
AB + BC + AC > 2 AD [Given BD+DC = BC]
AB + BC + AC > 2 AD
hence Proved
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