In the given figure, DE || AB and FE || DB. Prove that DC2 = CF . AC [CBSE 2007]
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Answered by
570
see the diagram that was missing from the question.
In ΔABC, we have CD/DA = CE/EB as AB || DE
in ΔCDB, we have CF/FD = CE/EB as EF || BD
hence we get CD/DA = CF/FD
=> Reciprocals: DA/CD = FD /CF
=> Add 1 on both sides: AC /CD = DC/CF
=> DC^2 = CF * AC
In ΔABC, we have CD/DA = CE/EB as AB || DE
in ΔCDB, we have CF/FD = CE/EB as EF || BD
hence we get CD/DA = CF/FD
=> Reciprocals: DA/CD = FD /CF
=> Add 1 on both sides: AC /CD = DC/CF
=> DC^2 = CF * AC
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kvnmurty:
i hope that is easy to understand...
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Answered by
178
here is ur answer guys
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