In the given figure, DE || BC such that AE = (1/4) AC. If AB = 6 cm, find AD.
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Given, DE || BC and AE = (1/4)AC and AB = 6 cm.
In ΔADE & ΔABC
∠A = ∠A
[Common]
∠ADE = ∠ABC
[Corresponding angles]
Then, ΔADE∼ΔABC
[By AA similarity ]
AD/AB = AE/AC
[Since, triangles are similar, hence corresponding sides will be proportional]
AD/6 = 1/4AC/AC
AD/6 = 1/4
4 x AD = 6
AD = 6/4
AD = 1.5 cm
Hence, the length of AD is 1.5 cm.
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