In the given figure, DE || BD. Determine AC and AE.
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SOLUTION :
Given : DE || BD
AB = 4cm , BC = 15cm , DE = 12cm , AD= 14 cm
In ∆ADE & ∆ ACB,
∠ADE = ∠C (corresponding angles as DE || BD)
∠A = ∠A (Common)
∆ADE ∼ ∆ACB
[By AA Similarity]
AE/ AB = DE/CB = AD/AC
[since Triangles are similar, hence corresponding sides will be proportional]
AE/4 = 12/15 = 14/AC
AE/4 = 12/15
15× AE = 12 × 4
AE = (12 × 4)/15
AE =( 4 × 4) /5
AE = 16/5
12/15 = 14/AC
12 × AC = 15 × 14
AC = (15×14)/12
AC = (5 × 14)/4
AC = 35/2
Hence, the value of AE is 16/5 & AC is 35/2.
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Answer:
AC = 35/2 AE = 16/5
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