Question

In the given figure DE II BC, if AD = x, DB=x-2, AE=x+2 and EC=x-1 then find the value of x.​

Answer 1

Answer:

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Step-by-step explanation:

Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.

To find: x

In △ABC, we have 

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4