in the given figure determine a,b,c
Attachments:
Answers
Answered by
11
a=90°
b=28°
c=62°
plzzzzz mark as brainlist
b=28°
c=62°
plzzzzz mark as brainlist
tanviii644:
okk
Answered by
13
Consider the cyclic quadrilateral AEDB,
∠BAE + ∠BDE = 180° [opposite angles of a cyclic quadrilateral are supplementary]
⇒ 62° + ∠BDE = 180°
⇒ ∠BDE = 180° - 62° = 118°
Again, ∠BDE + ∠BDC = 180° [Linear pair angles]
⇒ 118° + ∠BDC = 180°
⇒ ∠BDC = 62°
⇒ ∠a = ∠BDC + ∠BCD [The exterior angle of a triangle is equal to sum of two interior opposite angles]
⇒ ∠a = 62° + 43° = 105°
Again, ∠a + ∠AED = 180° [As opposite angles of a cyclic quadrilateral are supplementary]
⇒ 105° + ∠AED = 180°
⇒ ∠AED = 75°
Now, in triangle DEF,
∠AED = ∠c + ∠b [Again, the exterior angle of a triangle is equal to sum of two interior opposite angles]
⇒ ∠c + ∠b = 75°
Now, the value of ∠c and ∠b can't be found from above equation based on the information provided by you.
Please recheck your query.
∠BAE + ∠BDE = 180° [opposite angles of a cyclic quadrilateral are supplementary]
⇒ 62° + ∠BDE = 180°
⇒ ∠BDE = 180° - 62° = 118°
Again, ∠BDE + ∠BDC = 180° [Linear pair angles]
⇒ 118° + ∠BDC = 180°
⇒ ∠BDC = 62°
⇒ ∠a = ∠BDC + ∠BCD [The exterior angle of a triangle is equal to sum of two interior opposite angles]
⇒ ∠a = 62° + 43° = 105°
Again, ∠a + ∠AED = 180° [As opposite angles of a cyclic quadrilateral are supplementary]
⇒ 105° + ∠AED = 180°
⇒ ∠AED = 75°
Now, in triangle DEF,
∠AED = ∠c + ∠b [Again, the exterior angle of a triangle is equal to sum of two interior opposite angles]
⇒ ∠c + ∠b = 75°
Now, the value of ∠c and ∠b can't be found from above equation based on the information provided by you.
Please recheck your query.
Similar questions