in the given figure, equilateral EBC surmount Square ABCD. find the value x
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Answer:
- x = 45°
Step-by-step explanation:
Given that equilateral triangle EBC surmount square ABCD.
All the sides of equilateral triangle and square are equal and the base of triangle is same as side of square. Therefore,
- AB = BC = CD = AD = CE = BE
We know that all the angles in an equilateral triangle is equal to 60° and all the angles of square are equal to 90°.
Consider ∆ ABE :
It is an equilateral triangle where BE = AB. angle opposite to equal sides are also equal. So, ∠AEB = ∠BAE.
Applying angle sum property of triangle in ∆ ABE :
∠ BAE + ∠ AEB + ABE = 180°
∠ AEB + ∠ AEB + ( 90° + 60° ) = 180°
2 ∠ AEB + 150° = 180°
2 ∠ AEB = 180° - 150°
2 ∠ AEB = 30°
∠ AEB = 15°
Now,
∠ CEB = ∠ CEF + ∠ AEB
60° = x + 15°
60° - 15° = x
45° = x
Therefore value of x is 45°.
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