in the given figure, find 3 tan theta - 2 sin a + 4 cos a
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3tan theta = 4
tan theta = 4/3= p/b
p= 4 , b= 3 , h= ?
we know that,
h²= (p)²- (b)²
h²= (4)²-(3)²
h²= 16-9= 7
h= ✓7.
Therefore,
sin theta = p/h = 4/✓7
cos theta = b/h = 3/✓7
Therefore,
=4Cos theta - Sin theta /2 Sin theta+ 6 Cos theta.
= 4×(3/✓7)- (4/✓7)/2(4/✓7)+6(3/✓7)= 4/13
tan theta = 4/3= p/b
p= 4 , b= 3 , h= ?
we know that,
h²= (p)²- (b)²
h²= (4)²-(3)²
h²= 16-9= 7
h= ✓7.
Therefore,
sin theta = p/h = 4/✓7
cos theta = b/h = 3/✓7
Therefore,
=4Cos theta - Sin theta /2 Sin theta+ 6 Cos theta.
= 4×(3/✓7)- (4/✓7)/2(4/✓7)+6(3/✓7)= 4/13
Answered by
1
Answer:
n the given figure, find 3 tan theta - 2 sin a + 4 cos a
Step-by-step explanation:
1.Find out tan theta
tan theta = perpendicular/base.
Base can be found by Pythagoras theorem in the bigger triangle.
2. Find out sin alpha, cos alpha from smaller triangle
hypotenuse can be found by Pythagoras theorem.
sin alpha =perpendicular/hypotenuse
cos alpha =base/hypotenuse.
3. Put all the values in the equation given.
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