Question

in the given figure, find 3 tan theta - 2 sin a + 4 cos a

Answer 1

3tan theta = 4
tan theta = 4/3= p/b
p= 4 , b= 3 , h= ?
we know that,
h²= (p)²- (b)²
h²= (4)²-(3)²
h²= 16-9= 7
h= ✓7.
Therefore,
sin theta = p/h = 4/✓7
cos theta = b/h = 3/✓7
Therefore,
=4Cos theta - Sin theta /2 Sin theta+ 6 Cos theta.
= 4×(3/✓7)- (4/✓7)/2(4/✓7)+6(3/✓7)= 4/13

Answer 2

Answer:

n the given figure, find 3 tan theta - 2 sin a + 4 cos a

Step-by-step explanation:

1.Find out tan theta

tan theta = perpendicular/base.

Base can be found by Pythagoras theorem in the bigger triangle.

2. Find out sin alpha, cos alpha from smaller triangle

hypotenuse can be found by Pythagoras theorem.

sin alpha =perpendicular/hypotenuse

cos alpha =base/hypotenuse.

3. Put all the values in the equation given.