In the given figure, find all the angles of ABC
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1
As angle EAF and angle BAC are vertically opposite angles they are equal and BAC=40 degrees.
Angle ACD is 105 degrees so ACB is equal to 180-105=75 degrees as angle ACD and ACB form a linear pair.
By angle sum property angles A, B and C sum up to 180 degrees.
So 40+75+angle B=180degrees.
Angle B= 65 degrees
Answered by
3
<A = 40 (vertically opposite angle)
<C = <C + <D = 180 (linear pair)
= <C + 105 = 180
= 180 - 105 = 75
<B = <A + <B + <C = 180 (angle sum property)
= 40 + <B + 75 = 180
= 115 + <B = 180
= 180 - 115 = <B
= 65
therefore, angles are
<A = 40
<B = 75
<C = 65
<C = <C + <D = 180 (linear pair)
= <C + 105 = 180
= 180 - 105 = 75
<B = <A + <B + <C = 180 (angle sum property)
= 40 + <B + 75 = 180
= 115 + <B = 180
= 180 - 115 = <B
= 65
therefore, angles are
<A = 40
<B = 75
<C = 65
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