Question

in the given figure,find angle ACD and angle AED .​

Answer 1

Answer:

75

Step-by-step explanation: let suppose ,<ACB= M

<A+<B+<M(ACB)=180(BEING SUM OF INTERIOR ANGLE OF A TRIANGLE)

OR, 25+37+M=180

OR,62+M=180

OR, M=180-62

.M=118

THEN, <ACD+<M=180 (STRAIGHT ANGLE)

OR,<ACD+118=180

OR, <ACD=180-118

.<ACD=62

AGAIN,

<ACD+<EDC+<AED=180(BEING SUM OF TWO OPPOSITE INTERIOR ANGLE OF A TRIANGLE)

<ACD+43+<AED=180

OR, 62+43+<AED=180

OR,<AED=180-105

..,<AED=75