Question

in the given figure find angle DCB if ae parallel to CD​

Answer 1

Answer:

30°

Step-by-step explanation:

If we continue the line EA to the BQ and give the mame to the point where EA touches BQ.

Then the angle EAB +angleBAG=180

Therefore

angle BAG=180-50=130

Now in triangleBAG

AngleB+angleA+angleG=180

20+130+angelG=180

150+angelG=180

AngleG=180-150=30°...........(answer).

Since AE||CD

Therefore angleG=angleC

Answer 2

Answer:

30

Step-by-step explanation:

correct answer