Question

In the given figure find < BCN. ​

Answer 1

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DAB~=180°-110°=70°

ADC= 180°-70°=110°

ie. sum of adjacent angle(dab+adc)= 180°

nowwww

≤DCB = 70°

≤ABC=110°

BCN angle+ angle DCB = 180°

BCN angle= 180°-70°= 110°