In the given figure, find the length x:
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In triangle PRS ,
by Pythagoras theorem
PR^2=PS^2-RS^2
=10^2-6^2
=64
PR=root64
=8
In triangle PRQ,
by Pythagoras theorem.
x^2=PQ^2-PR^2
=17^2-8^2
=225
X=root225
x=15
:-)pls mark as brainliest.
by Pythagoras theorem
PR^2=PS^2-RS^2
=10^2-6^2
=64
PR=root64
=8
In triangle PRQ,
by Pythagoras theorem.
x^2=PQ^2-PR^2
=17^2-8^2
=225
X=root225
x=15
:-)pls mark as brainliest.
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