Question

in the given figure, find the measure of angle C A B, angle abc angle ACB.

Answer 1

1) angle CAB = angle FAE =45°
(Vertic. opp.)
3) Now in triangle ABC
ACB = (180-105)°
=75°
2) We now that the sum of triangle
=ABC+BAC+ACB=180°
=ABC+45°+75°=180°
=ABC=180°-120°
=60°

Hope its help you

Answer 2

Answer:

∠ABC = 60° , ∠CAB=45° and ∠ACB=75°

Step-by-step explanation:

∠FAE =∠CAB (vertically opposite angles)

∠FAE =∠CAB=45°

In ΔABC

∠ABC+∠CAB = ∠ACD(exterior angle property)

∠ABC = 105°-45°

∠ABC = 60°

In ΔABC

∠ABC+∠CAB+∠ACB=180°(Angle sum property of triangle)

60°+45°+∠ACB=180°

105°+∠ACB=180°

∠ACB=180°-105°

∠ACB=75°

Hence∠ABC = 60° , ∠CAB=45° and ∠ACB=75°