In the given figure, find the value of x.
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AB II to DC, then ∠BAE = ∠CDE= 50°
∠DEC= 180- (∠DCE + ∠CDE)
x=180°-(50°+35°)
x=180-85
x=95°
∠DEC= 180- (∠DCE + ∠CDE)
x=180°-(50°+35°)
x=180-85
x=95°
Answered by
12
AB parallel CD
angle BAE=angle EDC
angle EDC=50 degree
we know that sum of all angle of triangle =180degree
angle E+angle D+angle C= 180 degree
E+35+50=180
E=180-85
E=95
so the value of x = 95 degree
please mark it as brainlist
angle BAE=angle EDC
angle EDC=50 degree
we know that sum of all angle of triangle =180degree
angle E+angle D+angle C= 180 degree
E+35+50=180
E=180-85
E=95
so the value of x = 95 degree
please mark it as brainlist
R113:
my pleasure sir
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