Question

In the given figure find the value of y !!!!!!!!!!


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Answer 1

your answer is in attachment.....

hope it's helpful to you..!

Good morning !

Answer 2

Find the value of y :

As, we can see that AB is a straight line, so

$\sf \angle AOB = 180\degree$

So,

$\therefore \sf \angle AOQ + \angle QOP + \angle POB = 180 \degree$

Putting the values,

3y + 40 + 2y = 180°

=> 5y + 40 = 180°

=> 5y = 180° - 40°

=> 5y = 140°

=> y = $\sf \frac{140\degree}{5}$

=> y = 28°

Hence, value of y = 28°

Also,

Value of $\sf \angle AOQ = 3y = 3 \times 28° = \bold{84°}$

Value of $\sf \angle POB = 2y = 2 \times 28° = \bold{56°}$