Question

In the given figure ,find x in which angle A is 5x-60°, angle B is 2x+40° and angle C is 3x-80°.​

Answer 1

Solution :

In the figure, the angles of a triangle are -

• (5x - 60)°
• (2x + 40)°
• (3x - 80)°

As we know that, the sum of all angles in a triangle is 180°. Therefore,

⇝ (5x - 60)° + (2x + 40)° + (3x - 80)° = 180°

⇝ (5 + 2 + 3)x + (-60 + 40 - 80) = 180°

⇝ 10x + (-140 + 40) = 180°

⇝ 10x - 100 = 180°

⇝ 10x = 180° + 100

⇝ x = 280°/10

⇝ x = 28°

∴ The value of x is 28°.

Answer 2

Given :-

• Angle A = 5x - 60° .
• Angle B = 2x + 40° .
• Angle C = 3x - 80° .

⠀⠀⠀⠀⠀⠀

To Find :-

• The value of X .

⠀⠀⠀⠀⠀⠀

Solution :-

⠀⠀⠀⠀⠀⠀

∓ Sum of angles in Traingle = 180° .

⠀⠀⠀⠀⠀⠀

• Now, let's solve -----

⠀⠀⠀⠀⠀⠀

$➞\:\sf{(5x-60)°+(2x+40)°+(3x-80)°=180°}$

$➞\:\sf{(5+2+3)x+(-60+40+80)=180°}$

$➞\:\sf{10x+(-140+40)=180°}$

$➞\:\sf{10x-100=180°}$

$➞\:\sf{10x=180°+100}$

$➞\:\sf{10x=280°}$

$➞\:\sf{x=280\:/\:10}$

$➞\:\sf\red{x=28°}$

⠀⠀⠀⠀⠀⠀

Hence :-

• The value of x = 28° .

___________________________________

$\large\colorbox{pink}{Hope lt'z Help You\:\:!! }$