Question

in the given figure from a sheet of cardboard in the shape of a square of side 14 cm,a piece in the shape of letter B is cut off the curved side of letter consists of two semicircular and the breadth of a rectangular piece is 1 centimetre find the area of remaining part of the cardboard

Answer 1

Answer:

.Area of B. (πr^2/2) x2 = πr^2

= πr^2 = 3.14x(I3/2)^2

= 132.665cm2

Area of square = a ^2 = 14 ^2 = 196

= 196cm^2

Remaining part =196-132.665

= 63.335 cm2. Ans

Answer 2

Area of remaining portion of cardboard=163.55 square cm

Step-by-step explanation:

Side of square =14 cm

Area of square=$side\times side$

Area of square=$14\times 14=196 cm^2$

Breadth of rectangle=1 cm

Diameter of outer  semi circle of letter B=$\frac{14}{2}=7 cm$

Radius of outer semi circle of letter B=$\frac{7}{2}cm$

Diameter of  inner semi circle=7-1-1=5 cm

Radius of inner semi- circle=$\frac{5}{2} cm$

Area of curved part of B=Area of outer semi- circle -area of inner semi- circle

Area of curved of letter B=$2\times \frac{1}{2}\times \frac{22}{7}\time( (\frac{7}{2})^2-\frac{1}{2}(\frac{5}{2})^2)=18.45 cm^2$

Area of  semi circle=$\frac{1}{2}\pi r^2$

r=Radius of circle

Area of rectangular part=$length\times breadth=14\times 1=14 cm^2$

Substitute the values then we get

Area of letter B=$14+18.45=32.45 cm^2$

Area of remaining portion of cardboard=196-32.45=163.55 square cm

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