In the given figure, if AB = 3 cm and AC = 5 cm, then CD is equal to
(a) 4 cm
(b) 2 cm
(c) 3 cm
(d) 5 cm
Answers
Answer:
AB^2 + BC^2 = AC^2
9 + BC^2 = 25
BC = 4 cm
CD = 4 cm ( BC = CD )
Hence, correct option is (a) 4 cm
Given : AB = 3 cm and AC = 5 cm
AC is bisector of angle BAD
To Find : CD
(a) 4 cm
(b) 2 cm
(c) 3 cm
(d) 5 cm
Solution:
ΔABC is right angle
Pythagoras theorem:
Square on the hypotenuse of a right-angled triangle is equal to the
sum of the squares of the other two perpendicular sides.
AC² = AB² + BC²
=> 5² = 3² + BC²
=> BC² = 4²
=> BC = 4 cm
in Δ ABC and ΔADC
∠BAC = ∠DAC as AC is bisector of angle BAD
∠ABC = ∠ADC = 90°
AC = AC common
=> ΔABC ≅ ΔADC using AAS congruence
Hence
BC = CD using corresponding parts of congruent triangles are equal
Hence , CD = 4 cm
Correct option is a) 4 cm
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