Question

in the given figure, if AB||CD||EF, PQ||RS, ∆CQP=60°, then find∆QRS.​

Answer 1

Answer:

(c) Given, PQ || RS

∠PQC = ∠BRS = 60° [alternate exterior angles and ∠PQC = 60° (given)] and ∠DQR = ∠QRA = 25° [alternate interior angles]

[∠DQR = 25°, given]

∠QRS = ∠QRA + ∠ARS

= ∠QRA + (180° – ∠BRS) [linear pair axiom]

= 25° + 180° – 60°= 205° – 60°= 145°

Step-by-step explanation:

Answer 2

Answer:

(c) Given, PQ || RS

∠PQC = ∠BRS = 60° [alternate exterior angles and ∠PQC = 60° (given)] and ∠DQR = ∠QRA = 25° [alternate interior angles]

[∠DQR = 25°, given]

∠QRS = ∠QRA + ∠ARS

= ∠QRA + (180° – ∠BRS) [linear pair axiom]

= 25° + 180° – 60°= 205° – 60°= 145

good night take care

it is option c